Question

$HCl$ cn be oxidised by:

• A. $KMn{O}_4$
• B. $C{l}_2$
• C. Conc. $H_{2}S{O}_4$
• D. $KMn{O}_4$ and Conc. $H_{2}S{O}_4$

Answer 1

The correct option is B $C{l}_2$

$H^{+}$ in $HCl$ is the reactant reduced, and $HCl$ is the oxidizing agent. $Zn$ is the reactant oxidized and the reducing agent. $C{u}^{2+}$ in $CuC{l}_2$ is the reactant reduced, and $CuC{l}_2$ is the oxidizing agent.$C{l}_2$ is the reactant reduced and the oxidizing agent.