1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Physics
Relative Velocity in 2D
he equation o...
Question
he equation of trajectory of a projectile is given as2y=2xThe maximum height of projectile is2(Symbols have usual meanings and Sl unit)15(1) 4 m(2) 1 mta 2 m(4) 10 m
Open in App
Solution
Suggest Corrections
69
Similar questions
Q.
The equation of trajectory of projectile is given by
y
=
x
√
3
−
g
x
2
20
, where
x
and
y
are in meter. The maximum range of the projectile is
Q.
The equation of trajectory of a projectile is
y
=
(
x
√
3
−
g
x
2
20
)
, where
x
and
y
are in meter. The maximum range of the projectile is (take
g
=
10
m
/
s
2
)
Q.
The equation of trajectory of a projectile is
y
=
(
x
√
3
−
g
x
2
20
)
, where
x
and
y
are in meter. The maximum range of the projectile is (take
g
=
10
m
/
s
2
)
Q.
The equation of trajectory of a projectile is
y
=
10
x
,
(
5
9
)
x
2
. If we assume
g
=
10
m
s
−
2
the range of projectile ( in metres) is:
Q.
Equation of trajectory of a projectile is
Y = bx -
5
9
x
2
.
What is the maximum height reached?
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Relative Motion in 2D
PHYSICS
Watch in App
Explore more
Relative Velocity in 2D
Standard XII Physics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app