Heat is being supplied at a constant rate to a sphere of ice which is melting at the rate of 0.1 gm/sec. It melts completely in 100 sec. The rate of rise of temperature thereafter will be (Assume no loss of heat)
A
0.8∘C/sec
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B
5.4∘C/sec
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C
3.6∘C/sec
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D
Will change with time
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Solution
The correct option is A0.8∘C/sec Required heat to melt 0.1 grams of ice per second is ΔQ/Δt=0.1×80=8cal/s
Amount of ice converted to water is =0.1×100=10gm
Rate of rise in temperature will be ΔTΔt=ΔQ/Δtms=8/(10×1)=0.8∘C/s.