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Question

Heat is being supplied at a constant rate to a sphere of ice which is melting at the rate of 0.1 gm/sec. It melts completely in 100 sec. The rate of rise of temperature thereafter will be (Assume no loss of heat)

A
0.8 C/sec
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B
5.4 C/sec
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C
3.6 C/sec
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D
Will change with time
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Solution

The correct option is A 0.8 C/sec
Required heat to melt 0.1 grams of ice per second is ΔQ/Δt=0.1×80=8 cal/s
Amount of ice converted to water is =0.1×100=10 gm

Rate of rise in temperature will be ΔTΔt=ΔQ/Δtms=8/(10×1)=0.8 C/s.

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