Heat is supplied to a diatomic gas at constant pressure. The ratio of $Δ Q : Δ U : W$ is :

5 : 3 : 2

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5 : 2 : 3

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7 : 5 : 2

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7 : 2 : 5

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Solution

The correct option is B $7 : 5 : 2$
For Isobaric process,

$Δ Q = n C_{p} Δ T$

$Δ U = n C_{v} Δ T$

$W = P Δ V = n R Δ T$

$Δ Q : Δ U : W = C_{p} : C_{v} : R$

For diatomic gas, number of degrees of freedom $f = 5$
$C_{v} = \frac{f R}{2} = \frac{5 R}{2}$

$C_{p} = C_{v} + R = \frac{5 R}{2} + R = \frac{7 R}{2}$

Therefore,

$Δ Q : Δ U : W = 7 : 5 : 2$

Suggest Corrections

Similar questions

Δ Q : Δ U : Δ W

γ

= \frac{7}{5}

C_{p} = \frac{7}{2} R

C_{v} = \frac{5}{2} R

d U : d Q : d W

In an isobaric process, the ratio of heat supplied to the system $Δ Q$ and work done by the system $Δ W$ for diatomic gas is

(v = 5 / 3)

(γ = 7 / 5)

γ

γ

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