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Combustion Reactions

Heat liberate...

Question

Heat liberated on complete combustion of 0.6 g of a fuel of calorific value 18.2 kj/g is utilized for heating 400g of water. Calculate the rise in temperature of water. ( specific heat of water is 4.2 j/ g/ degree c)

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Solution

1. q = mc(T₂-T₁)
2. q = 0.6 * 18.2 = 10.92 kj/g

10.92 kj/g = 400 * 4.2 * (T₂-25)
T₂ = 25.0065

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