wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Heat of atomisation of NH3 and N2H4 are x kcalmol1 and y kcalmol1 respectively. What will be average bond energy of NN?

A
3y4x3 kcal mol1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3y4x3 kcal mol1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
3y+4x3 kcal mol1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of the above
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 3y4x3 kcal mol1
Given reactions are:
NH3N(g)+3H(g) ΔHatom=x kcal mol1=ΔH1=3×BENH......1
N2H42N(g)+4H(g) ΔHatom=y kcal mol1=ΔH2=4×BENH+BENN......2
from equation 1 we have
BENH=x3
put BENH in equation 2 to get the value of BENN
ΔatomH=y kcal mol1=ΔH2=4×x3+BENN
BENN=y4x3
BENN=3y4x3 kcal mol1
hence, the average bond energy of NN is 3y4x3 kcal mol1

flag
Suggest Corrections
thumbs-up
3
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon