Question

Heat of hydrogenation of ethene is $x_1$ and that of Benzene is $x_2$ Hence resonance energy is ?

• A. $x_1-x_2$
• B. $x_1+x_2$
• C. $3x_1-x_2$
• D. $x_1-3x_2$

Answer 1

Answer: (C)

$3x_1-x_2$

Energy of ethene $=x_1$

Number of ethene in benzene$=3$.

Therefore,

Observed energy of hydrogenation of benzene $=3x_1$

Calculated energy of hydrogenation of benzene $=x_2\left(\text{Given}\right)$

Therefore,

Reseonance energy $=$ observed - calculated $=3x_1-x_2$