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B
>57.32KJ
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C
<57.32KJ
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D
None of these
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Solution
The correct option is B >57.32KJ Heat of neutralisation of HF is > 57.32 KJ as heat will be released in the ionisation of HF HF→HP+F−ΔH ΔH is - ve HP+OH−→H2OΔH=−57.32KJ