You visited us 8 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Limiting Reagent or Reactant

Heat of neutr...

Question

Heat of neutralisation of strong acid and strong base is constant and is equal to:

57.3 KJ mol

^{- 1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

13.7 KJ mol

^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

22.4 KJ mol

^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

52.3 KJ mol

^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 57.3 KJ mol $^{- 1}$
Heat of neutralisation of strong base and strong acid is constant and is equal to 57.3 $K J m o l^{- 1}$ as they all consists of same equation

$H^{+} + O H^{-} \to H_{2} O, Δ H = - 57.3 K J m o l^{- 1}$

Option A is correct.

Suggest Corrections

Similar questions

Q. The enthalpy of neutralisation of strong acid by a strong base is

- 57.32 k J m o l^{- 1}

. The enthalpy of formation of water is

- 285.84 k J m o l^{- 1}

. The enthalpy of formation of hydroxyl ion is :

The heat of neutralisation of a strong acid by a strong base is 57.3 KJ mol $^{- 1}$ . The heat released when 0.5 mol HNO $_{3}$ is mixed with 0.2 mol KOH in aqueous medium is:

Q. The enthalpy of neutralisation of a weak acid of 1M solution with a strong base is

- 56.1

KJ/ mol . If the enthalpy of ionisation of acid is 1.5 KJ

m o l^{- 1}

and enthalpy of neutralisation of the acid with a strong base is

- 57.3

e q^{- 1}

, what is the

%

ionisation of the weak acid in molar solution?

Q. Enthalpy of neutralisation of acetic acid by

N a O H

- 50.6 k J m o l^{- 1}

. Calculate

Δ H

for ionisation of

C H_{3} C O O H

. Given, the heat of neutralisation of a strong acid with a strong base is

- 55.9 k J m o l^{- 1}

Δ H_{f}^{0}

of water is

- 285.8 k J {m o l}^{- 1}

. If enthalpy of neutralisation of monoacid strong base is

- 57.3 k J {m o l}^{- 1}, Δ H_{f}^{0}

O H^{-}

ion will be:

Join BYJU'S Learning Program

Heat of neutralisation of strong acid and strong base is constant and is equal to:

The correct option is A 57.3 KJ mol −1Heat of neutralisation of strong base and strong acid is constant and is equal to 57.3 KJmol−1 as they all consists of same equation H++OH−→H2O,ΔH=−57.3KJmol−1Option A is correct.

The correct option is A 57.3 KJ mol $^{- 1}$
Heat of neutralisation of strong base and strong acid is constant and is equal to 57.3 $K J m o l^{- 1}$ as they all consists of same equation

$H^{+} + O H^{-} \to H_{2} O, Δ H = - 57.3 K J m o l^{- 1}$

Option A is correct.