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Acidity of Alcohols and Phenols

Heat of neutr...

Question

Heat of neutralization is less negative than -13.7 Kcal/mole for the reaction:

H C l + N a O H \to N a C l + H_{2} O

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H_{2} S O_{4} + 2 N a O H \to N a_{2} S O_{4} + 2 H_{2} O

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H N O_{3} + N a O H \to N a N O_{3} + H_{2} O

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C H_{3} C O O H + N a O H \to C H_{3} C O O N a + H_{2} O

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Solution

The correct option is D $C H_{3} C O O H + N a O H \to C H_{3} C O O N a + H_{2} O$
The enthalpy of neutralization ( $Δ H_{n}$ ) is the change in enthalpy that occurs when one equivalent of an acid and one equivalent of a base undergo a neutralization reaction to form water and salt.

The heat of neutralization is less negative for reactions of a weak acid strong base, strong acid weak base and weak acid weak base.

Hence, the correct option is $D$

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Similar questions

H C l + N a O H \to N a C l + H_{2} O + x c a l .

H_{2} S O_{4} + 2 N a O H \to N a_{2} S O_{4} + 2 H_{2} O + y c a l

H N O_{3} + C a {(O H)}_{2} \to C a {(N O_{3})}_{2} + H_{2} O

N a O H + H_{2} S O_{4} \to {N a}_{2} S O_{4} + H_{2} O

N a C l + A g N O_{3} \to A g C l + N a N O_{3}

B a {C l}_{2} + H_{2} S O_{4} \to B a S O_{4} + H C l

H C l + N a O H \to N a C l + H_{2} O + x c a l

H_{2} S O_{4} + 2 N a O H \to N a_{2} S O_{4} + 2 H_{2} O + y c a l

x

y

57.1 k J

{m o l}^{- 1}

0.25

N a O H

0.25

H C l

N a O H + H C l \to N a C l + H_{2} O

Find the odd-man-out.

(a) HNO₃, H₂SO₄, HCl, Na₂CO₃

(b) MgO, CaO, H₂O, Na₂O

(d) NaCl, C₁₂H₂₂O₁₁, KCl, CuSO₄

(e) HCl, H₂SO₄, HNO₃, CH₃COOH

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