Heat of neutralization of $H C l$ and $N a O H$ is $x$ kJ and that of $C H_{3} C O O H$ and $N a O H$ is $y$ kJ. What is heat of ionization of $C H_{3} C O O H$ .

(x - y)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(y - x)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(x + y)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- (x + y)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $(y - x)$ kJ
i) $H C L + N a O H \to N a C l + H_{2} O$ ; $Δ$ $H = x K J$
ii) $C H_{3} C O O H + N a O H \to C H_{3} C O O N a + H_{2} O$ ; $Δ H = y K J$
Reversing (i) and adding (ii) gives,
$N a C l + C H_{3} C O O H \to C H_{3} C O O N a + H C l; Δ H (y - x) K J$
(iii) $C H_{3} C O O H \to C H_{3} C O O^{-} + H^{+}; Δ H (y - x) K J$
The equation (iii) gives the heat of ionization of $C H_{3} C O O H$

Suggest Corrections

Similar questions

^{- 1}

- x

k J

- y

k J

- z

k J

^{'} - x^{'} k J

^{'} - y^{'} k J

^{'} z^{'} k J

Δ H_{t}

C (g r a p h i t e) + O_{2} (g) \to C O_{2} (g)

Δ H = x k J

C (d i a m o n d) + O_{2} (g) \to C O_{2} (g)

Δ H = y k J

Join BYJU'S Learning Program