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Heat of Reaction

Heat of neutr...

Question

Heat of neutralization of NaOH and HCl is -57.46 kJ/equivalent. The heat of ionisation of water in kJ/mol is:

A

-57.46

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B

57.46

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C

-114.92

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D

114.92

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Solution

The correct option is C 57.46
The expression for the neutralization of NaOH and HCl can be represented as:

$H^{+} + O H^{-} ⇌ H_{2} O; Δ H = - 57.46 k J$

The expression for the ionization of water can be represented as:

$H_{2} O ⇌ H^{+} + O H^{-}; Δ H = + 57.46 k J$

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