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Question

Heat of reaction for the reaction is:


PCl5(g)+H2O(g)POCl3(g)+2HCl(g)

Given that,
Pwhite+(3/2)Cl2(g)+12O2(g)POCl3;ΔH=135.5kcal
H2(g)+Cl2(g)+2HCl(g);ΔH=44.1kcal
P(w)+(5/2)Cl2(g)PCl5(g);ΔH=89.6kcal
H2(g)+12O2(g)H2O(g);ΔH=57.8kcal

A
32.2kcal
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B
52.5kcal
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C
45.2kcal
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D
None of these
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Solution

The correct option is A 32.2kcal
Pwhite+32Cl2(g)+12O2(g)POCl3;ΔH1=135.5kcal

H2(g)+Cl2(g)+2HCl(g);ΔH2=44.1kcal

P(w)+52Cl2(g)PCl5(g);ΔH3=89.6kcal

H2(g)+12O2(g)H2O(g);ΔH4=57.8kcal
The final reaction is obtained by reversing 3 and 4 and adding 1 and 2 to it:

PCl5(g)+H2O(g)POCl3(g)+2HCl(g)

ΔH=ΔH1+ΔH2ΔH3ΔH4.

ΔH=135.544.1+89.6+57.8

=32.2kcal

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