Question

Heat required to melt $1g$ of ice is $80cal$. A man melts $60g$ of ice by chewing in one minute. His power is :

• A. $1.33W$
• B. $0.75W$
• C. $336W$
• D. $4800W$

Answer 1

Answer: (C)

$336W$

$Q=mL$ , where $L$ is latent heat, $80cal=80\times 4.2J$

Power $P=\frac{Q}{t}$ ,where $t$ is time in seconds

Power is $\frac{60\times 80\times 4.2}{60}=336W$