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Introduction to Electrophilic Substitution

Heating benze...

Question

Heating benzene in a large excess of $80 %$ $D_{2} S O_{4}$ in $D_{2} O$ results in what product?

C_{6} H_{5} S O_{3} D

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C_{6} H_{5} O D

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C_{6} H_{5} D

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C_{6} D_{6}

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Solution

The correct option is A $C_{6} H_{5} S O_{3} D$
$D_{2} S O_{4} + D_{2} O ⟶ D_{3} O^{+} + S O_{3} D$
The benzene undergoes nucleophilic aromatic substution reaction.
(refer to image)
Therefore,benzene in large excess of $80$ % $D_{2} S O_{4}$ in $D_{2} O$ results in $C_{6} H_{5} S O_{3} D$

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Similar questions

D_{4} {S O}_{2}

D_{2} O

{S O}_{3}

D_{2} O

C a C_{2} + 2 D_{2} O \to C_{2} D_{2} + C a (O D)_{2}

S O_{3} + D_{2} O \to D_{2} S O_{4}

A l_{4} C_{3} + 12 D_{2} O \to 3 C D_{4} + 4 A l (O D)_{3}

C_{2} D_{2} + O_{2} \to C O_{2} + D_{2} O

C D_{4} + O_{2} \to C O_{2} + D_{2} O

C a C_{2}, S O_{3} & A l_{4} C_{3}

3 : 2 : 1

O_{2}

D_{2} O

D_{2} O

0^{o}

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