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Borax

Heating benze...

Question

Heating benzene in a large excess of 80% $D_{4} {S O}_{2}$ in $D_{2} O$ results in what product?

C_{6} H_{5} {S O}_{3} D

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C_{6} H_{5} O D

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C_{6} H_{5} D

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C_{6} D_{6}

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Solution

The correct option is D $C_{6} D_{6}$
It replaces all H of benzene so product formed is $C_{6} D_{6}$ .

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C_{6} H_{5} {N H}_{2}

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C_{6} H_{5} {N H}_{2}

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C_{6} H_{6}

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C_{6} H_{5} - C H_{2} - C H = C H_{2} + H B r \to

C_{6} H_{5} - C H = C H_{2} + H B r P e r o x i d e - ---- \to

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