Question

Heating in current carrying conductor is a product of and time.

• A. current
• B. resistance
• C. power

Answer 1

The correct option is C power

Heating effect $\left(H\right)$ in a current carrying conductor depends on power $\left(P\right)$ through the conductor and time $\left(t\right)$.
Let $R$ be the resistance and $V$ be the voltage.
Therefore, $H=I^2\times R\times t=\frac{V^2}{R}\times t$
where $P=I^2\times Ror\frac{V^2}{R}$
$\Rightarrow H=P\times t$