Heating together of sodium ethoxide and ethyl iodide will give:

ethyl alcohol

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acetaldehyde

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diethyl ether

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acetic acid

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Solution

The correct option is C diethyl ether
$C_{2} H_{5} O N a + C_{2} H_{5} I D r y e t h e r - ----- \to C_{2} H_{5} - O - C_{2} H_{5} + N a I$

Heating together of sodium ethoxide and ethyl iodide forms diethyl ether.

This is Williamson's ether synthesis.

As alkyl halide is primary ethoxide will acts as nucleophile.

Nucleophilic substitution reaction takes place ( $S_{N} 2$ )

Option C is correct.

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