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Standard VII

Mathematics

Solving Equations with Linear Expressions on One Side and Numbers on the Other Side

Heena has onl...

Question

Heena has only rs. 2 and rs. 5 coins in her purse. If in all she has 80 coins in her purse amounting to rs. 232, find the number of 5 coins.

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Solution

Total number of coins=80
Let the number of 2 rs. coins=x
The number of 5 rs. coins = 80-x
According to given statement,
$2 x + 5 (80 - x) = 232$
$⟹ 2 x + 400 - 5 x = 232$
$⟹ - 3 x = 232 - 400$
$⟹ - 3 x = - 168$
$⟹ x = 56$
Number of 5 rs. coins = 80-x = 80 -56=24
Number of 5 rs. coins= 24

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Heena has only rs. 2 and rs. 5 coins in her purse. If in all she has 80 coins in her purse amounting to rs. 232, find the number of 5 coins.

Total number of coins=80Let the number of 2 rs. coins=x The number of 5 rs. coins = 80-xAccording to given statement, 2x+5(80−x)=232⟹2x+400−5x=232⟹−3x=232−400⟹−3x=−168⟹x=56Number of 5 rs. coins = 80-x = 80 -56=24Number of 5 rs. coins= 24

Total number of coins=80
Let the number of 2 rs. coins=x
The number of 5 rs. coins = 80-x
According to given statement,
$2 x + 5 (80 - x) = 232$
$⟹ 2 x + 400 - 5 x = 232$
$⟹ - 3 x = 232 - 400$
$⟹ - 3 x = - 168$
$⟹ x = 56$
Number of 5 rs. coins = 80-x = 80 -56=24
Number of 5 rs. coins= 24