Question

Heena takes 3 bulbs out of box A which has 7 bulbs. I take 3 bulbs out of box B. Which of the following can be the possible number of bulbs in box B, if my fraction is lesser than Heena's fraction?

• A. 4 boxes
• B. 8 boxes
• C. 6 boxes
• D. 5 boxes

Answer 1

The correct option is B 8 boxes

Heena's fraction = $\frac{3}{7}$

If box B has 4 bulbs, my fraction = $\frac{3}{4}$
If box B has 6 bulbs, my fraction = $\frac{3}{6}$
If box B has 5 bulbs, my fraction = $\frac{3}{5}$
If box B has 8 bulbs, my fraction = $\frac{3}{8}$

For fractions with the same numerator, we compare the denominators.
Higher the denominator, lower the fraction.
Hence, $\frac{3}{4}>\frac{3}{5}>\frac{3}{6}>\frac{3}{7}>\frac{3}{8}$
Since my fraction is lesser than Heena's fraction, my fraction must be $\frac{3}{8}$.

Therefore, Box B needs to have 8 bulbs.