Height of atmosphere, if atmospheric density is $1.29 k g m^{- 3}$ and atmospheric pressure is $101 k P a$ , is

7839.4 m

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7829.4 m

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7849.4 m

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7859.4 m

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Solution

The correct option is B $7829.4 m$
Density of atmosphere $ρ = 1.29 k g m^{- 3}$
Atmospheric pressure $P = 101 k P a = 101 \times 1000 P a$
Pressure at the surface due atmosphere above of height $h$ is given by $P_{a t m} = ρ g h$
$⟹ 101 \times 1000 P a = 1.29 k g m^{- 3} \times 10 m s^{- 2} \times h$
$⟹ h = 7829.4 m$

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Height of atmosphere, if atmospheric density is 1.29kgm−3 and atmospheric pressure is 101kPa, is

The correct option is B 7829.4mDensity of atmosphere ρ=1.29kgm−3Atmospheric pressure P=101kPa=101×1000PaPressure at the surface due atmosphere above of height h is given by Patm=ρgh⟹101×1000Pa=1.29kgm−3×10ms−2×h⟹h=7829.4m

Height of atmosphere, if atmospheric density is $1.29 k g m^{- 3}$ and atmospheric pressure is $101 k P a$ , is