Question

Helium gas at 1 atm and $S{O}_2$ at 2 atm pressure, temperature being the same, are released seprately at the same moment into 1m long evacuated tubes of equal diameters. If helium reaches the other end of the tube in ts, what distance $S{O}_2$ would traverse in the same time interval in the other tube ?

• A. 25 cm
• B. 50 cm
• C. 60 cm
• D. 75 cm

Answer 1

The correct option is

B

50 cm

Given:

The pressure of Helium gas = 1 atm.

The pressure of = 2 atm.

Distance, (x) = 1 m = 100cm

To find the distance covered by to reach other tube with the same interval of time is given by,

$\frac{r_{He}}{r_{S{O}_2}}=\frac{\frac{100}{t}}{\frac{x}{t}}=\frac{P_{He}}{P_{S{O}_2}}\sqrt{\frac{M_{S{O}_2}}{M_{He}}}=\frac{1}{2}\times \sqrt{\frac{64}{4}}=2$
or $x=50cm$

The distance covered by to other tube is 50 cm.