Hello,
Please help me with following problem :

In a two digit no. , the unit's digit exceeds tens digit by 2. The product of the given number and the sum of digits is equal to 144. Find the number.

regards,
Nikita

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Solution

Let the ten's digit be x.

Then, unit's digit = x + 2.

Number = 10x + (x + 2) = 11x + 2

Sum of digits = x + (x + 2) = 2x + 2.

(11x + 2) (2x + 2) = 144

=> 22x^2+26x-140=0

=> (x - 2)(11x + 35) = 0

=> x = 2

Hence, Required Number = 11x + 2 = 24

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Hello, Please help me with following problem : In a two digit no. , the unit's digit exceeds tens digit by 2. The product of the given number and the sum of digits is equal to 144. Find the number. regards, Nikita

Let the ten's digit be x. Then, unit's digit = x + 2. Number = 10x + (x + 2) = 11x + 2 Sum of digits = x + (x + 2) = 2x + 2. (11x + 2) (2x + 2) = 144 => 22x^2+26x-140=0 => (x - 2)(11x + 35) = 0 => x = 2 Hence, Required Number = 11x + 2 = 24

Hello,
Please help me with following problem :

In a two digit no. , the unit's digit exceeds tens digit by 2. The product of the given number and the sum of digits is equal to 144. Find the number.

regards,
Nikita

Let the ten's digit be x.

Then, unit's digit = x + 2.

Number = 10x + (x + 2) = 11x + 2

Sum of digits = x + (x + 2) = 2x + 2.

(11x + 2) (2x + 2) = 144

=> 22x^2+26x-140=0

=> (x - 2)(11x + 35) = 0

=> x = 2

Hence, Required Number = 11x + 2 = 24