Question

Help Anna with her homework by solving the given expression:

$\frac{4\times A}{3\times B}÷\frac{3\times A}{4\times B}$

• A. 1
• B. $\frac{A}{B}$
• C. $\frac{16}{9}$
• D. $\frac{9}{16}$

Answer 1

The correct option is C $\frac{16}{9}$

$\text{Calculating}\frac{4\times A}{3\times B}÷\frac{3\times A}{4\times B}\text{using the}keep-change-flip\text{method, we get:}$


$\text{Calculating}\frac{4\times A}{3\times B}\times \frac{4\times B}{3\times A}\text{, we get:}$

$\frac{4\times A}{3\times B}\times \frac{4\times B}{3\times A}=\frac{4\times A\times 4\times B}{3\times B\times 3\times A}=\frac{4\times A\times 4\times B}{3\times B\times 3\times A}=\frac{4\times 4}{3\times 3}=\frac{16}{9}$