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Question

Help Sana identify the smallest natural number that can be multiplied with the fraction 8115 such that the decimal expansion of the resulting fraction is terminating.

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Solution

8115 has 15 in its denominator.

15=3×5

To make the fraction a terminating decimal, we need to eliminate 3 in the denominator by multiplying a number that is a multiple of 3.

Since we are asked for the smallest such natural number, we go with 3 itself.

8115×3=8×15+13×5×3=1215

Now, the denominator is a multiple of 5. Hence, it will result in a terminating decimal number.

In fact,1215=24.2, which is a terminating decimal.

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