Hemoglobin contains 0.334% of iron by weight. The molecular weight of hemoglobin is approximately 67200. The number of iron atoms (Atomic weight of Fe is 56 ) present in one molecule of hemoglobin is:

5 atoms

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4 atoms

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2 atoms

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None of these

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Solution

The correct option is B 4 atoms
The molecular weight of haemoglobin= $67200$
It contains $0.334$ % of iron by weight.
Weight of iron= $\frac{0.334}{100} \times 67200 = 224.448$
$N o . o f a t o m s = \frac{W e i g h t o f i r o n i n h a e m o g l o b i n}{A t o m i c w e i g h t} = \frac{224.448}{56} = 4.008$
No. of iron atoms present in one molecule of haemoglobin is $4$ .

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Haemoglobin contains 0.33% of iron by weight . The molecular weight of haemoglobin is approximately 67200 . The number of iron atoms ( at . wt. of Fe=56) present in one molecule of haemoglobin is

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Hemoglobin contains 0.334% of iron by weight. The molecular weight of hemoglobin is approximately 67200. The number of iron atoms (Atomic weight of Fe is 56 ) present in one molecule of hemoglobin is:

The correct option is B 4 atomsThe molecular weight of haemoglobin=67200It contains 0.334% of iron by weight.Weight of iron=0.334100×67200=224.448No. of atoms=Weight of iron in haemoglobinAtomic weight=224.44856=4.008No. of iron atoms present in one molecule of haemoglobin is 4.