Question

Hence, $\Delta ADC$ and $\Delta BAC$ are similar.

If the above statement is true then mention answer as 1, else mention 0 if false

Answer 1

In $△ADC$ and $△ABC$,
$\angle ADC=\angle BAC$ (Each ${90}^{\circ }$)
$\angle ACD=\angle ACB$ (Common angle)
$\angle DAC=\angle ABC$ (Third angle)
Thus, $△ADC\sim △BAC$ (AAA postulate)