Henry's law constant for the molality of methane in benzene at 298 K is 4.27×105 mm Hg. Calculate the solubility of methane in benzene at 298 K under 760 mm Hg.

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Solution

K_H=4.27×10₅ mm Hg (at 298K)
p = 760 mm
Applying Henry's law
p=KH× [x = Mole fraction/solubility of methane]
x=p/KH=(760 mm)/(4.27×10⁵ mm)=1.78×10⁻⁵=1.78×10⁻³

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Henry’s law constant for the molality of methane in benzene at 298 Kis 4.27 × 10⁵ mm Hg. Calculate the solubility of methane in benzene at 298 Kunder 760 mm Hg.

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Henry's law constant for the molality of methane in benzene at 298 K is 4.27×105 mm Hg. Calculate the solubility of methane in benzene at 298 K under 760 mm Hg.

KH=4.27×105 mm Hg (at 298K)p = 760 mmApplying Henry's lawp=KH× [x = Mole fraction/solubility of methane]x=p/KH=(760 mm)/(4.27×105 mm)=1.78×10−5=1.78×10−3

K_H=4.27×10₅ mm Hg (at 298K)
p = 760 mm
Applying Henry's law
p=KH× [x = Mole fraction/solubility of methane]
x=p/KH=(760 mm)/(4.27×10⁵ mm)=1.78×10⁻⁵=1.78×10⁻³