Henry-s law constant for the molality of methane in benzene at 298 K is 4-27 - 105 mm Hg- Calculate the solubility of methane in benzene at 298 K under 760 mm Hg-

It is given that the molality of methane in benzene at 298 K is 4.27× 10^5 mm of Hg. C = pk C = 760 mm Hg4.27 × 10^5 mm Hg / m ...

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Standard XII

Chemistry

Solubility Product

Henry's law c...

Question

Henry's law constant for the molality of methane in benzene at $298 K$ is $4.27 \times 105 m m H g$ . Calculate the solubility of methane in benzene at $298 K$ under $760 m m H g$ .

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Solution

It is given that the molality of methane in benzene at $298 K$ is $4.27 \times 10^{5}$ mm of Hg.

$C = \frac{p}{k}$

$C = \frac{760 m m H g}{4.27 \times 10^{5} m m H g / m}$

$C = 1.78 \times 10^{- 3}$ m

Here, C is the molality of methane in benzene, p is the pressure of methane and k is Henry's law constant.

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Henry’s law constant for the molality of methane in benzene at 298 Kis 4.27 × 10⁵ mm Hg. Calculate the solubility of methane in benzene at 298 Kunder 760 mm Hg.

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Henry's law constant for the molality of methane in benzene at 298 K is 4.27×105 mm Hg. Calculate the solubility of methane in benzene at 298 K under 760 mm Hg.

It is given that the molality of methane in benzene at 298 K is 4.27×105 mm of Hg.C=pkC=760mmHg4.27×105mmHg/mC=1.78×10−3 mHere, C is the molality of methane in benzene, p is the pressure of methane and k is Henry's law constant.

Henry's law constant for the molality of methane in benzene at $298 K$ is $4.27 \times 105 m m H g$ . Calculate the solubility of methane in benzene at $298 K$ under $760 m m H g$ .