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Question


Here, (A), (B), (C), (D), (E), (F) ,(G) and (H) are as follows:

(A) : (NH4)2Cr2O7 (B) : NH3 (C) : Cr2O3
(D) : N2 (E) : AlN (F) : CrCl3 (G) : Na2CrO4
(H) : PbCrO4

Write the above reaction.

169458_5bdec92b1e03417ab560db51fe442ad3.png

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Solution

Orange coloured ammonium dichromate (compound A) on heating forms nitrogen gas (compound D ) and residue C which is chromium (III) oxide and green in colour.
(NH4)2Cr2O7ΔN2+Cr2O3+4H2O
When ammonium dichromate is heated in presence of NaOH, ammonia gas (compound B) is evolved.
(NH4)2Cr2O7+2NaOHΔ2NH3+2H2O+Na2O+2CrO3
Ammonia reacts with HCl to form white fumes of ammonium chloride.
NH3+HClNH4Clwhite fumes
When nitrogen is heated with aluminum, aluminum nitride is obtained.
2Al+N2heat2AlNE
AlN on hydrolysis forms aluminum hydroxide and ammonia gas (compound B).
AlN+3H2OAl(OH)3+NH3.
Chromium trioxide on treatment with HCl forms chromic chloride (compound F).
Cr2O3+6HCl2CrCl3+3H2O
Chromic chloride on heating with NaOH and hydrogen peroxide forms sodium chromate (compound G).
2CrCl3+4NaOH+2H2O2heat2Na2CrO4+6HCl+H2
Sodium chromate reacts with acetic acid and lead acetate to form yellow precipitate of lead chromate which is compound (H).
Na2CrO4+(CH3COO)2PbCH3COOH−−−−−−PbCrO4yellow+2CH3COONa

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