Question

Here AB $\parallel$ CD. If the altitude of $△$ACD is 6 cm and CD is 8 cm then the area of $△$BCD is _____.

• A. $14c{m}^2$
• B. $24c{m}^2$
• C. $34c{m}^2$
• D. $44c{m}^2$

Answer 1

The correct option is B

$24c{m}^2$

Two triangles on the same base (or equal bases) and between the same parallels are equal in area.

$\therefore$ Area($△$ACD) = Area($△$BCD)
Area($△$ACD) $=\frac{1}{2}\times 8\times 6$

$=24c{m}^2$

$\therefore$ Area($△$BCD) $=24c{m}^2.$