Here AB ∥ CD. If the altitude of △ACD is 6 cm and CD is 8 cm then the area of △BCD is:
Triangle between the same parallels and sharing same base have equal areas.
So, Area(△ACD) = Area(△BCD)
Now, Area(△ACD) = 12×8×6=24 cm2
∴ Area(△BCD) = 24 cm2
Here, AB ∥ CD. If the altitude of △ACD is 6 cm and CD is 8 cm, then the area of △BCD is:___.
Here AB ∥ CD. If the altitude of △ACD is 6 cm and CD is 8 cm then the area of △BCD is _____.
In a quadrilateral ABCD AB = 6 cm, BC = 8 cm, CD = 8 cm and AC=10cm.The area of the quadrilateral is 60.67 cm2. Find DA. [4 MARKS]