Question

Heterolysis of propane gives?

• A. $\stackrel{\bullet }{C}{H}_3$ and $\stackrel{\bullet }{C_2}{H}_5$
• B. $C{H}_3^{⨁}$ and $C_2^{⨁}{H}_5$
• C. $C{H}_3^{\ominus }$ and $C_2^{⨁}{H}_5$
• D. $C{H}_3^{⨁}$ and $C{H}_3^{+}$ and $C{H}_2^{-}$

Answer 1

The correct option is C $C{H}_3^{\ominus }$ and $C_2^{⨁}{H}_5$

$\begin{array}{c}\text{Breaking of a bond forming a cation}\\ \text{and anion.}\\ \text{Propane:}{H}_{3}C-C{H}_2-C{H}_3\end{array}$

$\begin{array}{c}{H}_{3}C-{CH}_2{-}^{}{CH}_3⟶{CH}_3^{-}+C_2{H}_5^{+}\\ \text{Inductive effect}\end{array}$