Hexa ammine nickel (II) hexa nitro cobaltate (III) can be written as:

[N i (N H_{3})_{6} C o (N O_{2})_{6}]

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[N i (N H_{3})_{6}]_{3} [C o (N O_{2})_{6}]_{2}

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[N i (N H_{3})_{6}] [C o (N O_{2})_{6}]_{2}

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[N i (N H_{3})_{6} (N O_{2})_{6}] C o

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Solution

The correct option is B $[N i (N H_{3})_{6}]_{3} [C o (N O_{2})_{6}]_{2}$
$[N i (N H_{3})_{6}]_{3} [C O (N O_{2})_{6}]_{2} \equiv 3 [N i (N H_{3})_{6}]^{2 +} | 2 [C O (N O_{2})_{6}]^{3 -}$
Since $3 N i (2 +)$ balance with $2 C o (3 +)$

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The two compounds sulphato penta-ammine cobalt(III) bromide and sulphato penta-ammine cobalt (III) chloride represent

1)linkage isomerism

2) ionisation isomerism

3)co ordination isomerism

4)no isomerism

N a_{3} [C o (N O_{2})_{6}]

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