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Question

Hg2+2+2e2Hg E0=0.789V
Hg2++2eHg E0=0.854V
Calculate the equilibrium constant for Hg2+2Hg+Hg2+ .

A
3.1×103
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B
3.1×104
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C
6.3×103
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D
6.3×104
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Solution

The correct option is C 6.3×103
Hg2+2+2e2HgE0=0.789 V
HgHg2++2eE0=0.854 V

Hg2+2Hg+Hg2+0.065 V

ΔG=2×(0.065)×96500=8.314×298 lnKeq
Keq=6.3×103.

Hence, option C is correct.

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