wiz-icon
MyQuestionIcon
MyQuestionIcon
3
You visited us 3 times! Enjoying our articles? Unlock Full Access!
Question

Hg2+2+2e2Hg E0=0.789V
Hg2++2eHg E0=0.854V
Calculate the equilibrium constant for Hg2+2Hg+Hg2+ .

A
3.1×103
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3.1×104
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
6.3×103
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
6.3×104
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 6.3×103
Hg2+2+2e2HgE0=0.789 V
HgHg2++2eE0=0.854 V

Hg2+2Hg+Hg2+0.065 V

ΔG=2×(0.065)×96500=8.314×298 lnKeq
Keq=6.3×103.

Hence, option C is correct.

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Equilibrium Constant from Nernst Equation
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon