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Van Arkel - De Boer Method

HgNO32W+X+O2 ...

Question

$H g {(N O_{3})}_{2} Δ - \to W + X + O_{2}$
$X + H_{2} O ⟶ H N O_{2} + H N O_{3}$
$W + H N O_{3} ⟶ Y + N O + H_{2} O$
$Y + N a_{2} S_{2} O_{3} (e x c e s s) ⟶ Z + N a N O_{3}$
Find $W$ , $X$ , $Y$ and $Z$

W = H g

X = N_{2} O

Y = H g {(N O_{3})}_{2}

Z = N a_{2} [H g {(S_{2} O_{3})}_{2}]

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W = H g O

X = N O

Y = H g {(N O_{3})}_{2}

Z = N a [H g {(S_{2} O_{3})}_{2}]

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W = H g

X = N O_{2}

Y = H g {(N O_{3})}_{2}

Z = N a_{2} [H g {(S_{2} O_{3})}_{2}]

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W = H g

X = N_{2} O_{3}

Y = H g {(N O_{3})}_{2}

Z = N a_{3} [H g {(S_{2} O_{3})}_{2}]

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Solution

The correct option is C $W = H g$ , $X = N O_{2}$ , $Y = H g {(N O_{3})}_{2}$ , $Z = N a_{2} [H g {(S_{2} O_{3})}_{2}]$
Option (C) is correct.
$\begin{matrix} H g {(N O_{3})}_{2} & Δ - \to & H g (l) & + & N O_{2} ↑ & + & O_{2} ↑ (W) & (X) \end{matrix}$
$2 N O_{2} + H_{2} O ⟶ H N O_{2} + H N O_{3}$
$\begin{matrix} H g & + & 4 H N O_{3} & Δ - \to & H g {(N O_{3})}_{2} & + & 2 N O ↑ & + & 2 H_{2} O (W) & (d i l .) & (Y) \end{matrix}$
$\begin{matrix} H g {(N O_{3})}_{2} & + & N a_{2} S_{2} O_{3} & ⟶ & N a_{2} [H g {(S_{2} O_{3})}_{2}] & + & 2 N a N O_{3} S o l u b l e \end{matrix}$

Suggest Corrections

Similar questions

{A g N O}_{3} Δ - \to (W) + (X) + O_{2}

(X) + H_{2} O ⟶ H {N O}_{2} + H {N O}_{3}

(W) + H {N O}_{3} ⟶ Y + N O + H_{2} O

(Y) + {N a}_{2} S_{2} O_{3} (excess) ⟶ Z + N a {N O}_{3}

(W)

(Z)

C a C O_{3} △ \to W + X

W + H_{2} O \to Y

Y + Z \to N a O H + C a C O_{3}

w < x < z

w < y < z

w < z

x < y

y < z

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