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Ion Electron Method

HgO is analys...

Question

$H g O$ is analysed by reaction with iodine and then titrating with an acid. The equivalent mass of $H g O$ is :
$H_{2} O + H g O + 4 I^{-} \to H g I_{4}^{2 -} + 2 O H^{-}$

M

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\frac{M}{2}

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\frac{M}{4}

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\frac{M}{3}

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Solution

The correct option is D $\frac{M}{2}$
$H_{2} O + H g O + 4 I^{-} \to H g I_{4}^{2 -} + 2 O H^{-}$
In this reaction, one mole of $H g O$ gives two moles of $O H^{-}$ ions, so Eq. wt. of $H g O$ is $\frac{M}{2}$ .

Suggest Corrections

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