Highest oxidation state of Mn is present in :

KMnO

_{4}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

_{2}

MnO

_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

_{2}

_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

none of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A KMnO $_{4}$
The oxidation state of $M n$ is

i. $K m n n O_{4}$

$1 + n - 4 (2) = 0$

$n = 7$

ii. $K_{2} n M n O_{4}$

$2 + n - 4 (2) = 0$

$n = 6$

iii. $M_{2} O_{3}$

$2 n - 3 (2) = 0$

$n = 3$

So, oxidation state of $M n$ iss highest in $K M n O_{4}$

Suggest Corrections

Similar questions

Q. The oxidation states of

M n

K_{2} M n O_{4}

and

K M n O_{4}

respectively are:

When MnO₂ is fused with KOH a coloured compound is formed. The product and its colour are

Q. When

M n O_{2}

is fused with KOH, a coloured compound is formed. The product and its colour is

Q. The reaction of aqueous

K M n O_{4}

with

H_{2} O_{2}

in acidic conditions gives

$M n O_{2}$ when fused with KOH and oxidized in air gives a dark green compound X. In acidic X. In acidic solution, X undergoes disproportion to give an intense purple compound Y and $M n O_{2}$ . The compounds X and Y respectively, are

Join BYJU'S Learning Program

Highest oxidation state of Mn is present in :

The correct option is A KMnO4The oxidation state of Mn is i. KmnnO4 1+n−4(2)=0 n=7 ii. K2nMnO4 2+n−4(2)=0 n=6 iii. Mnn2O3 2n−3(2)=0 n=3 So, oxidation state of Mn iss highest in KMnO4

The correct option is A KMnO $_{4}$
The oxidation state of $M n$ is

i. $K m n n O_{4}$

$1 + n - 4 (2) = 0$

$n = 7$

ii. $K_{2} n M n O_{4}$

$2 + n - 4 (2) = 0$

$n = 6$

iii. $M_{2} O_{3}$

$2 n - 3 (2) = 0$

$n = 3$

So, oxidation state of $M n$ iss highest in $K M n O_{4}$