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B
(CH3)2NH
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C
(CH3)3N
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D
CH3NH2
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Solution
The correct option is BNH3 Due to hyperconjugation basic strength and thus the pKb value decreases so the molecule which is having no hyperconjugation must have highest pKb values.
Here NH3 does not have any hyperconjugation does it has the highest value of pKb.