Highest value of $p K_{b}$ will be of:

N H_{3}

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{(C H_{3})}_{2} N H

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{(C H_{3})}_{3} N

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C H_{3} N H_{2}

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Solution

The correct option is B $N H_{3}$
Due to hyperconjugation basic strength and thus the $p K_{b}$ value decreases so the molecule which is having no hyperconjugation must have highest $p K_{b}$ values.
Here $N H_{3}$ does not have any hyperconjugation does it has the highest value of $p K_{b}$ .

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