HM between the roots of the equation x2-10x+11=0 is
15
521
2120
115
Explanation for the correct option:
Let p and q be the roots of the equation x2-10x+11=0.
Now,
Sum of roots is
p+q=-ba=10
Product of roots is
pq=ca=11
∴HM of p,q=2pq(p+q)
=21110=2210=115
Hence option(D) is correct.
No. of real roots of the equation x3+x2 + 10x + sin x = 0, is :