HNO2 - 2H2SO3 -H2O - NH2OH - 2D Then -D- is

HNO_2+2H_2SO_3+H_2O → NH_2OH+2H_2SO_4 ...

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Chlorides of Phosphorus

HNO2 + 2H2SO3...

Question

$H N O_{2} + 2 H_{2} S O_{3} + H_{2} O \to N H_{2} O H + 2 D T h e n ‘ D^{'} i s$

$S O_{2}$

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$S O_{3}$

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$H_{2} S O_{4}$

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$H N O_{3}$

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Solution

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$H N O_{2} + 2 H_{2} S O_{3} + H_{2} O \to N H_{2} O H + 2 D T h e n ‘ D^{'} i s$

Balance this equation ( I )No2+H2O=HNo2+HNO3

{C r_{2} O_{7}}^{2 -} + H N O_{2} + H^{+} \to C r^{3 +} + {N O_{3}}^{-} + H_{2} O

H g {(N O_{3})}_{2} Δ - \to W + X + O_{2}

X + H_{2} O ⟶ H N O_{2} + H N O_{3}

W + H N O_{3} ⟶ Y + N O + H_{2} O

Y + N a_{2} S_{2} O_{3} (e x c e s s) ⟶ Z + N a N O_{3}

W

X

Y

Z

{A g N O}_{3} Δ - \to (W) + (X) + O_{2}

(X) + H_{2} O ⟶ H {N O}_{2} + H {N O}_{3}

(W) + H {N O}_{3} ⟶ Y + N O + H_{2} O

(Y) + {N a}_{2} S_{2} O_{3} (excess) ⟶ Z + N a {N O}_{3}

(W)

(Z)

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