Ho w to solve t+3/2=1/5

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Solve : $\frac{2 x + 3}{5} > \frac{4 x - 1}{2}, x ϵ W .$

\frac{2 x + 3}{5} > \frac{4 x - 1}{2}, x ϵ W

t - (2 t + 5) - 5 (1 - 2 t) = 2 (3 + 4 t) - 3 (t - 4)

\frac{t + 2}{3} + \frac{1}{t + 1} = \frac{t + 3}{2} - \frac{t - 1}{6}

\frac{t + 2}{3} + \frac{1}{t + 1} = \frac{t + 3}{2} - \frac{t - 1}{6}

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