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Hoe many curi...

Question

Hoe many curies are contained in the radioactive change with activity $18.5 \times 10^{10}$ dps?

A

5

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B

4

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C

3

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D

1

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Solution

The correct option is A 5
$1 C = 3.7 \times 10^{10} d p s$
Hence, $\frac{18.5 \times 10^{10} d p s}{3.7 \times 10^{10} d p s} = 5 C$ are contained in the radioactive change with activity $18.5 \times 10^{10} d p s$

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