Homologue of $C_{3} H_{4}$ is :

C_{4} H_{6}

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C_{2} H_{6}

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C H_{3} O H

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H C H O

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Solution

The correct option is A $C_{4} H_{6}$
A homologous series is a family of hydrocarbons with similar chemical properties that share the same general formula.
The general formula of the compound in the question is $C_{n} H_{2 n - 2}$ with $n = 3$ .
Only the compound in option $A$ satisfies the given general formula with $n = 4$ .
So, homologue of $C_{3} H_{4}$ is $C_{4} H_{6}$ .

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