Horizontal force $F$ required to keep the cylinder in static equilibrium, if it is placed on a smooth horizontal plane.

3.5 N

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5 N

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7.2 N

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3 N

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Solution

The correct option is C $7.2 N$
In the given figure.
$\begin{matrix} 600 k s / m^{3} - 60 c m 900 k s / m^{3} - \frac{60 \times 2}{3} = 40 c m v = \sqrt{2 g h} = \sqrt{2 \times 10 \times \frac{80}{100}} = 4 m / s f = f_{t h u r s t} f = ρ a v^{2} f = 900 \times \frac{.5 \times 16}{100 \times 100} = 7.2 N \end{matrix}$
So,
Option $C$ is correct answer.

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Q. Horizontal force

F

to keep the cylinder in static equilibrium, if it is placed on a smooth horizontal plane, is

A cylindrical tank having cross-sectional area A = 0.5 $m^{2}$ is filled with two liquids of density $ρ_{1}$ = 900 kg $m^{- 3}$ and $ρ_{2}$ = 600 kg $m^{- 3}$ , to a height h = 60 cm each as shown in figure. A small hole having area a = 5 $c m^{2}$ is made in right vertical wall at a height y = 20 cm from the bottom. A horizontal force F is applied on the tank to keep it in static equilibrium. The tank is lying on a horizontal surface. Neglect mass of cylindrical tank comparison to mass of liquids. Horizontal force F to keep the cylinder in static equilibrium, if it is placed on a smooth horizontal plane