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Question

Hot coffee in a thermos flask is shaken vigorously, considering it as a system which of the statement is not true?


A

Work is done on the system

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B

Temperature of the system rises

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C

Heat energy has been added to coffee

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D

Internal energy of the coffee increased

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Solution

The correct option is C

Heat energy has been added to coffee


As thermos flask is insulated, so no heat is added to the system. Hence, ∆Q = 0.

Work is done on the system by shaking it against viscous force. Hence, ∆w is negative.

Temperature of the system rises because of increase in internal energy.

Internal energy of coffee ∆U = ∆Q - ∆W = 0 - (-∆W)

So, ∆U would be positive.


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