Hot copper turnings can be used as an oxygen getter for inert gas supplies by slowly passing the gas over the turnings at 600 K- 2Cus - 1-2O2g - Cu2Os- Kp - 7-5-1010atm-1-2The number of molecules of O2 are left in one litre of a gas supply after equilibrium has been reached is X- 10X is-

K_p = P_O_2^ 0.5 P_O_2 =(K_P)^ 2 = (7.5 × 10^10)^ 2= 1.77 × 10^ 22 atmVolume is 1 L and temperature is 600 K. The number of moles #160; #160;n ...

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Standard XII

Physics

Introduction

Hot copper tu...

Question

Hot copper turnings can be used as an oxygen getter for inert gas supplies by slowly passing the gas over the turnings at $600 K$ .
$2 C u (s) + 1 / 2 O_{2} (g) ⇌ C u_{2} O (s); K_{p} = 7.5 \times 10^{10} {a t m}^{- 1 / 2}$
The number of molecules of $O_{2}$ are left in one litre of a gas supply after equilibrium has been reached is $X$ . $10 X$ is__________.

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Solution

$K_{p} = P_{O_{2}}^{- 0.5}$
$P_{O_{2}} = (K_{P})^{- 2} = (7.5 \times 10^{10})^{- 2} = 1.77 \times 10^{- 22}$ atm

Volume is 1 L and temperature is 600 K. The number of moles
$n = \frac{P V}{R T} = \frac{1.77 \times 10^{- 22} \times 1}{0.08206 \times 600} = 3.61 \times 10^{- 24}$

The number of oxygen molecules is obtained by multiplying number of moles with Avogadro's number.

Number of oxygen molecules $= 3.61 \times 10^{- 24} \times 6.023 \times 10^{23} = 2.2$

But it is equal to X
$X = 2.2$
$10 X = 22$

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