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Byju's Answer
Standard IX
Mathematics
Addition and Subtraction of Integers
HOTS - I am a...
Question
HOTS
- I am an even integer between -3 and 7 - I am less than 6 but more than - 2
- I am not the additive inverse of - 6 - I am not equal to 4 + (-2)
- I am my own opposite THE MYSTIFY INTEGER is --------------------?
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Solution
The
even
integers
between
-
3
and
7
are
-
2
,
0
,
2
,
4
and
6
Here
0
is
an
even
integer
because
it
can
be
written
as
an
integral
multiple
of
2
.
That
is
,
0
=
2
×
0
for
0
belong
to
integers
.
Since
the
required
integer
is
less
than
6
and
more
than
-
2
,
it
cannot
be
equal
to
either
-
2
and
6
.
Also
,
it
is
given
that
it
is
not
an
additive
inverse
of
-
6
.
The
additive
inverse
of
-
6
is
6
because
the
sum
of
-
6
and
6
equals
0
,
the
additive
identity
.
So
now
it
is
confimed
that
the
number
is
not
6
.
Now
we
are
left
with
only
3
integers
0
,
2
,
4
It
is
further
given
that
the
number
is
not
equal
to
4
+
-
2
Evaluate
4
+
-
2
as
follows
:
4
+
-
2
=
4
-
2
=
2
So
the
required
number
is
not
equal
to
2
.
Now
we
are
left
with
only
two
even
integers
0
and
4
.
Apply
the
last
condition
that
the
required
number
is
opposite
of
itself
.
Since
the
number
4
is
not
opposite
of
itself
,
we
are
left
with
only
one
even
integer
,
0
The
even
integer
0
satisfies
the
condition
that
it
is
opposite
of
itself
.
Hence
the
required
even
integer
is
0
Suggest Corrections
0
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