How are xenon fluorides XeF₂, XeF₄ and XeF₆ obtained?

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Solution

XeF₂, XeF_4, and XeF₆ are obtained by a direct reaction between Xe and F2. The condition under which the reaction is carried out determines the product.

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How are xenon fluorides $X e F_{2}, X e F_{4}$ and $X e F_{6}$ obtained?

Q. Oxidising power of xenon fluorides increases in the order:

X e F_{6} > X e F_{4} > X e F_{2}

If true enter 1, else enter 0.

Xenon forms three binary fluorides $X e F_{2}, X e F_{4}$ and $X e F_{6}$ . All the three fluorides are colourless crystalline solids sublimating at 295K. They are powerful fluorinating agents and they are readily hydrolysed by water.
The shape of $X e O_{3}$ is:

Q. Hybridisation state of

X e

X e F_{2}

X e F_{4}

, and

X e F_{6}

respectively are:

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How are xenon fluorides XeF2, XeF4 and XeF6 obtained?

XeF2, XeF4, and XeF6 are obtained by a direct reaction between Xe and F2. The condition under which the reaction is carried out determines the product.

How are xenon fluorides XeF₂, XeF₄ and XeF₆ obtained?

XeF₂, XeF_4, and XeF₆ are obtained by a direct reaction between Xe and F2. The condition under which the reaction is carried out determines the product.